Write a C program to calculate the following Sum: Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10!

#include <stdio.h> #include <math.h> void main() { int counter,f_coun; float sum=0,x,power,fact; clrscr(); printf("PROGRAM FOR SUM OF EQ. SERIES"); printf("\n\n\tEQUATION SERIES : 1- X^2/2! + X^4/4! - X^6/6! + X^8/8! - X^10/10!"); printf("\n\tENTER VALUE OF X : "); scanf("%f",&x); for(counter=0, power=0; power<=10; counter++,power=power+2) { fact=1; //CALC FACTORIAL OF POWER VALUE for(f_coun=power; f_coun>=1; f_coun--) fact *= f_coun; //EQ. FOR SUM SERIES sum=sum+(pow(-1,counter)*(pow(x,power)/fact)); } printf("SUM : %f",sum); getch(); } Output: PROGRAM FOR SUM OF EQ. SERIES EQUATION SERIES : 1- X^2/2! + X^4/4! - X^6/6! + X^8/8! - X^10/10! ENTER VALUE OF X : 4 SUM : -0.685785