Write a C program to read in two numbers, x and n, and then compute the sum of this geometric progression: 1+x+x2+x3+………….+xn

Write a C program to read in two numbers, x and n, and then compute the sum of this geometric progression: 1+x+x2+x3+………….+xn For example: if n is 3 and x is 5, then the program computes 1+5+25+125. Print x, n, the sum Perform error checking. For example, the formula does not make sense for negative exponents – if n is less than 0. Have your program print an error message if n<0, then go back and read in the next pair of numbers of without computing the sum. Are any values of x also illegal ? If so, test for them too.   Program: #include<stdio.h> #include<conio.h> #include<math.h> void main() { int s_sum,i,x,n; clrscr(); printf("Enter the values for x and n:"); scanf("%d %d",&x,&n); if(n<=0 || x<=0) { printf("Value is not valid\n"); } else { s_sum=1; for(i=1;i<=n;i++) { s_sum=s_sum+pow(x,i); } printf("Sum of series=%d\n",s_sum); } getch(); } /* Output: Enter the values for x and n:2 4 Sum of series=31 */